Vector Is Not A Template

Vector Is Not A Template - If we start in node.h, early on, it includes edge.h. Since you're passing a pointer to a vector you need to dereference it before using the subscript operator. If you just accept std::vector, your some_func will reject std::vectors with alternative allocators.</p> It is not true that the type is not known. Template void some_func( std::vector<t,a> const& vec ) { } the second argument is the allocator, and in some advanced usage of std::vector it will not be the default one. The type of the vector you want to create is of the same kind of iter.

So, you should do something like: Since you're passing a pointer to a vector you need to dereference it before using the subscript operator. Commented jun 24, 2020 at 9:39. // wrong std::cin >> (*vector)[i]; You have to do this because vector is defined in the std namespace and you do not tell your program to find it in std namespace, you need to tell that.

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The same result can however be achieved by simply including in the header file, this way you are not dependant on the order of inclusion. When you forward declared the class as generic then at line 15 the compiler found the declaration. Template void some_func( std::vector<t,a> const& vec ) { } the second argument is the allocator, and in some.

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When you forward declared the class as generic then at line 15 the compiler found the declaration. // wrong std::cin >> (*vector)[i]; Just get iter underlying type either using decltype or using iterator type trait as follows: Template void some_func( std::vector<t,a> const& vec ) { } the second argument is the allocator, and in some advanced usage of std::vector it.

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The solution is to #include in the header hero.h, not the source file.</p> This however is rather unwielding. If you just accept std::vector, your some_func will reject std::vectors with alternative allocators.</p> But when you changed the declaration with template then the class generic is no longer found. It is not true that the type is not known.

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So, you should do something like: #ifndef file_h #define file_h #include std::vector showbytes(char const* filename); Vector in the function signature. But when you changed the declaration with template then the class generic is no longer found. Since you're passing a pointer to a vector you need to dereference it before using the subscript operator.

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But when you changed the declaration with template then the class generic is no longer found. If you just accept std::vector, your some_func will reject std::vectors with alternative allocators.</p> When you forward declared the class as generic then at line 15 the compiler found the declaration. Since you're passing a pointer to a vector you need to dereference it before.

Vector Is Not A Template - The same result can however be achieved by simply including in the header file, this way you are not dependant on the order of inclusion. Template void some_func( std::vector<t,a> const& vec ) { } the second argument is the allocator, and in some advanced usage of std::vector it will not be the default one. If we start in node.h, early on, it includes edge.h. Public cfg { generic *visitor; It is not true that the type is not known. You have to do this because vector is defined in the std namespace and you do not tell your program to find it in std namespace, you need to tell that.

The type of the vector you want to create is of the same kind of iter. Vector in the function signature. // wrong std::cin >> (*vector)[i]; If you just accept std::vector, your some_func will reject std::vectors with alternative allocators.</p> #ifndef file_h #define file_h #include std::vector showbytes(char const* filename);

Vector In The Function Signature.

The solution is to #include in the header hero.h, not the source file.</p> So, you should do something like: You have to do this because vector is defined in the std namespace and you do not tell your program to find it in std namespace, you need to tell that. It is not true that the type is not known.

But When You Changed The Declaration With Template Then The Class Generic Is No Longer Found.

The same result can however be achieved by simply including in the header file, this way you are not dependant on the order of inclusion. Template void some_func( std::vector const& vec ) { } the second argument is the allocator, and in some advanced usage of std::vector it will not be the default one. Since you're passing a pointer to a vector you need to dereference it before using the subscript operator. Building on what ganesh said, if you arrived here anytime after 2019, you need #include and the std::vector to use a vector.

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If you just accept std::vector, your some_func will reject std::vectors with alternative allocators.</p> The code is parsed in the order it appears. The type of the vector you want to create is of the same kind of iter. As some commenters have noted, you have circular references.

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If we start in node.h, early on, it includes edge.h. Vector is a template, not a type, you need the template argument list e.g. Commented jun 24, 2020 at 9:39. #ifndef file_h #define file_h #include std::vector showbytes(char const* filename);